Accu 2 is divided by accu 1 and the result is stored in accu 1. The remainder gets lost. As long as the values in accu 1 and accu 2 are positive it is indifferent whether they are loaded out of a word or a dword. But if one of the as word loaded operands can be negative ‘/D’ will lead to an absurd result. In this case the eventually negative operand has to be extended to the Dword-format with the operation ITD before dividing.
The remainder of the division can be kept with the operation MOD.
L L#300000
L MD 8
/D
T MD 20 // in MD 20 is now displayed 300000 / MD8
See also:
EN-input and ENO-output